def has_duplicate_naive(items):
    n = len(items)
    for i in range(n):
        for j in range(i + 1, n):
            if items[i] == items[j]:
                return True
    return False

print(has_duplicate_naive([3, 1, 4, 1, 5]))  # True
print(has_duplicate_naive([3, 1, 4, 9, 5]))  # False