A new array containing only the elements at those three positions

A single boolean indicating those indices exist

An error, since NumPy does not allow list-based indexing

The element at column index 2 from rows 0 and 1

By assigning a new tuple to the array's .shape attribute

Shape can only ever be changed with reshape()

Pass a sliced view of the array, such as arr[::2], into np.nditer()

np.nditer() cannot skip elements under any circumstance

It stacks them on top of each other as rows in a 2D array

It merges them into a single flat 1D array

It returns an index placed after all matching existing entries instead of before them

It returns the same index regardless of the side argument

It searches from the end of the array toward the start

No, it only ever accepts a single scalar value

Yes, by passing an array of values as the second argument

Only if the array is first converted to a Python list

The entire array is flattened and sorted as one sequence

A 2x3 array of random floats between 0 and 1

A new shuffled copy is returned while the original stays unchanged

The original array is deleted from memory

The dimensions must be equal, or one of them must be 1

The arrays must always have the exact same number of dimensions

NumPy Quiz